Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
For example, you may serialize the following tree
1 / \ 2 3 / \ 4 5as
"[1,2,3,null,null,4,5]"
, just the same as how LeetCode OJ serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself.
Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
Solution:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Codec { // Encodes a tree to a single string. public String serialize(TreeNode root) { if (root == null) { return null; } StringBuilder sb = new StringBuilder(); Queuequeue = new LinkedList (); queue.add(root); while (!queue.isEmpty()) { TreeNode node = queue.poll(); if (node == null) { sb.append("null,"); } else { sb.append(node.val + ","); queue.add(node.left); queue.add(node.right); } } return sb.toString(); } // Decodes your encoded data to tree. public TreeNode deserialize(String data) { if (data == null || data.length() == 0) { return null; } String[] vals = data.split(","); if (vals[0] == "null") { return null; } TreeNode root = new TreeNode(Integer.parseInt(vals[0])); Queue queue = new LinkedList (); queue.add(root); for (int i = 1; i < vals.length; i = i + 2) { TreeNode node = queue.poll(); if (!vals[i].equals("null")) { TreeNode n = new TreeNode(Integer.parseInt(vals[i])); queue.add(n); node.left = n; } if (!vals[i + 1].equals("null")) { TreeNode n = new TreeNode(Integer.parseInt(vals[i + 1])); queue.add(n); node.right = n; } } return root; } } // Your Codec object will be instantiated and called as such: // Codec codec = new Codec(); // codec.deserialize(codec.serialize(root));
No comments:
Post a Comment