Given an input string, reverse the string word by word.
For example,
Given s = "
return "
Given s = "
the sky is blue",return "
blue is sky the".
Clarification:
- What constitutes a word?
A sequence of non-space characters constitutes a word. - Could the input string contain leading or trailing spaces?
Yes. However, your reversed string should not contain leading or trailing spaces. - How about multiple spaces between two words?
Reduce them to a single space in the reversed string.
Solution:
O(n) runtime, O(n) space
One simple approach is a two-pass solution: First pass to split the string by spaces into an array of words, then second pass to extract the words in reversed order.
One simple approach is a two-pass solution: First pass to split the string by spaces into an array of words, then second pass to extract the words in reversed order.
We can do better in one-pass. While iterating the string in reverse order, we keep track of a word’s begin and end position. When we are at the beginning of a word, we append it.
public class Solution {
public String reverseWords(String s) {
StringBuilder result = new StringBuilder();
int len = s.length();
for(int i = s.length() - 1; i >= 0; i--) {
if(s.charAt(i) == ' ') {
len = i;
}else if(i == 0 || s.charAt(i - 1) == ' ') {
if(result.length() != 0) {
result.append(' ');
}
result.append(s.substring(i, len));
}
}
return result.toString();
}
}
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